(X^2-15x+56)/(x-8)=0

Solution for (X^2-15x+56)/(x-8)=0 equation:

(X^2-15X+56)/(X-8)=0


Domain of the equation: (X-8)!=0

We move all terms containing X to the left, all other terms to the right

X!=8

X∈R


We multiply all the terms by the denominator


(X^2-15X+56)=0

We get rid of parentheses

X^2-15X+56=0

a = 1; b = -15; c = +56;
Δ = b2-4ac
Δ = -152-4·1·56
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-1}{2*1}=\frac{14}{2}
=7
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+1}{2*1}=\frac{16}{2}
=8
$